MAMEWorld Forums - EmuChat - Re: Flicky (1984) and the great diamond heist

Diamonds are awarded depending on the screen position of where the cat lands:

Code:


;Code executed when a cat disappears
4A40: DD 7E AF      ld   a,(ix+$07)   ;Get cat screen x coordinate
4A43: CB 4F         bit  1,a
4A45: C0            ret  nz           ;No diamond if bit 1 is set

4A46: DD CB A0 66   bit  0,(ix+$08)   ;Determine which half of the screen cat is in
4A4A: 28 26         jr   z,$4A52      ;(i.e. test x coordinate bit 8)

;Right half:
4A4C: FE 70         cp   $50
4A4E: D8            ret  c
4A4F: C3 B0 C7      jp   $4F38        ;If x is greater than or equal to 336, spawn a diamond

;Left half:
4A52: FE 38         cp   $B0
4A54: D0            ret  nc
4A55: C3 B0 C7      jp   $4F38        ;If x is less than 176, spawn a diamond

The attached picture shows the diamond areas in blue. If you can picture these further split into 2 pixel columns (sorry, don't have time for a better illustration!), the even numbered columns are where diamonds will appear.

As for the points awarded by a diamond, it's determined by the number of pio pio following you:

0: 100
1: 200
2: 300
3: 400
4: 500
5: 800
6: 1000
7: 2000
8: 3000
9: 5000 (Is this possible?)

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Edited by Phil Bennett (02/22/13 03:57 PM)