> > It's been pouring rain to the tune of 2" per hour for the last 3 hours, and I got a > > little water in my basement.
Cannot complain this time around. Just about tied at this point for the worst flooding we've seen in the last 5 years. All the mitigation seems to have worked, I'm in decent shape all things considered.
> > I'm more than happy to share my "Liquid Gold" if you have 1000 miles of garden hose > to spare. > > Assuming that one had a 1000 mile length of hose laid flat and straight on the > ground, would it be possible to actually pump water through it? > > Thanks for the sleepless night.
Only if the diameter was as big as the Mississippi River is wide.
> > I'm more than happy to share my "Liquid Gold" if you have 1000 miles of garden hose > to spare. > > Assuming that one had a 1000 mile length of hose laid flat and straight on the > ground, would it be possible to actually pump water through it? > > Thanks for the sleepless night.
Assuming flat and straight, sure. The water would seek the lowest position available, and you'd only need enough pressure to overcome the surface tension.
The problem comes when it has to go up even a slight incline. Then the weight of the water would be such that the hose would burst, if you could even apply enough pressure.
With the mention of a garden hose and sucking pressure, I was kinda imagining this thread degenerating in a different direction than it is...
But as it is...
>you'd only need enough pressure to overcome the surface tension.
WHa? Surface tension forces are not even a factor except at the mouth of the pipe, which are ignored because they approach zero in relevance.
where: Φ is the volumetric flow rate V is a volume of the liquid poured (cubic meters) t is the time (seconds) v is mean fluid velocity along the length of the tube (meters/second) x is a distance in direction of flow (meters) R is the internal radius of the tube (meters) ΔP is the pressure difference between the two ends (pascals) η is the dynamic fluid viscosity (pascal-second (Pa·s)), L is the total length of the tube in the x direction (meters).
You'll note that the distance over which the flow rate is calculated is in the denominator, and pressure is in the numerator, meaning with the immense distance needed to travel, the corresponding pressure would have to be immense. Without even calculating it, the hose burst strength would be exceeded a million fold before you could push a single drop of water out at the other side.
edit: That being said, an Archimedes Screw would negate the need for pressure.. and that's what italie and I are working on. He said he was good at that, so that's where we are.
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